If I want to remove all ones from a string using boost::erase_all, I can do this:
boost::erase_all( "a1b1c1", "1" );
Now, my string is "abc". However, if I want to remove all digits (0 - 9) from a string, using boost::erase_all, I have to call it once for each digit I wish to remove.
boost::erase_all( "a1b2c3", "1" );
boost::erase_all( "a1b2c3", "2" );
boost::erase_all( "a1b2c3", "3" );
I thought I could use boost::is_any_of to remove them all at once as that works with other boost string algorithms such as boost::split, but is_any_of does not seem to work with erase_all:
boost::erase_all( "a1b2c3", boost::is_any_of( "123" ) );
// compile error
boost/algorithm/string/erase.hpp:593:13: error: no matching
function for call to ‘first_finder(const
boost::algorithm::detail::is_any_ofF<char>&)’
Perhaps I've over-looked something obvious here or there's another function within boost that's meant to do this. I can do it manually with standard C++, but just curious how others might be using boost to do this.
Thanks for any advice.
boost has a version of remove_if that doesn't require you to pass in begin and end iterators, but you will still need to call erase on the string with the end iterator.
#include <boost/range/algorithm/remove_if.hpp>
...
std::string str = "a1b2c3";
str.erase(boost::remove_if(str, ::isdigit), str.end());