I have class in which I am sorting a list.
import java.util.*;
public class First
{
private static HashMap<String,Second> msgs;
public static void main(String[] args)
{
List<String> ls=new ArrayList<String>();
ls.add("fourth");
ls.add("2");
ls.add("second");
ls.add("first");
ls.add("third");
ls.add("1");
Iterator it=ls.iterator();
// before sorting
while(it.hasNext())
{
String s=(String)it.next();
System.out.println(s);
}
Collections.sort(ls, new Comparator(){
public int compare(Object o1, Object o2) {
return -1;
// it can also return 0, and 1
}
});
System.out.println(" ");
//after sorting
Iterator iti=ls.iterator();
while(iti.hasNext())
{
String s=(String)iti.next();
System.out.println(s);
}
}
}
After the program is run, I get these values:
1
third
first
second
2
fourth
My question is what is the behavior of Collection.sort() function here. On returning -1 from compare function, we get the reverse order of the list. Then how can we get other sorting orders? What is the role of returning 0, and 1?
Finally, I modified the sort function in this manner to get sorted data.
Collections.sort(ls, new Comparator(){
public int compare(Object o1, Object o2)
{
String sa = (String)o1;
String sb = (String)o2;
int v = sa.compareTo(sb);
return v; // it can also return 0, and 1
}
});