I have a folder structure as follows:
mydomain.example
->Folder-A
->Folder-B
I have a string from Database that is ../Folder-B/image1.jpg
, which points to an image in Folder-B
.
Inside a script in Folder-A
, I am using dirname(__FILE__)
to fetch the filename and I get
mydomain.example/Folder-A
. Inside this script, I need to get a string that says 'mydomain.example/Folder-B/image1.jpg
. I tried
$path=dirname(__FILE__).'/'.'../Folder-B/image1.jpg';
This shows up as mydomain.com%2FFolder-A%2F..%2FFolder-B%2Fimage1.jpg
This is for a Facebook share button, and this fails to fetch the correct image. Anyone know how to get the path correctly?
I hope to get a URL: mydomain.example%2FFolder-B%2Fimage1.jpg
For PHP < 5.3 use:
$upOne = realpath(dirname(__FILE__) . '/..');
In PHP 5.3 to 5.6 use:
$upOne = realpath(__DIR__ . '/..');
In PHP >= 7.0 use:
$upOne = dirname(__DIR__, 1);