Why there are no std::wostream_iterator in C++?
Is there any good reason for this?
#include <fstream>
#include <iterator>
#include <string>
#include <vector>
int main()
{
std::vector<std::wstring> myvec = { L"first", L"second" };
std::wofstream f("New.txt");
// std::copy(myvec.begin(), myvec.end(), std::wostream_iterator<std::wstring>(f)); // Error
// std::copy(myvec.begin(), myvec.end(), std::ostream_iterator<std::wstring>(f)); // Error
std::copy(myvec.begin(), myvec.end(), std::ostream_iterator<std::wstring, wchar_t>(f)); // Ok
std::copy(myvec.begin(), myvec.end(), std::ostream_iterator<std::wstring, wchar_t, std::char_traits<wchar_t>>(f)); // Ok
}
Because std::ostream_iterator
is not typedef
(and std::wstring
is typedef on std::basic_string
with charT
= wchar_t
).
template <class T, class charT = char, class traits = char_traits<charT> >
class ostream_iterator:
public iterator<output_iterator_tag, void, void, void, void>
Second copy operation
std::copy(myvec.begin(), myvec.end(), std::ostream_iterator<std::wstring>(f));
is incorrect, since
typedef basic_ostream<charT,traits> ostream_type;
so, in this case ostream_type
is basic_ostream<char, std::char_traits<char> >
ostream_iterator(ostream_type& s);
Constructor can receive only this type, but we pass basic_ofstream<wchar_t, std::char_traits<wchar_t> >
, it's incorrect.