javaautomated-testsrft

How do I get the RFT version number?


How can a Rational Functional Tester script figure out under which version of RFT it executes/was built with?

I digged through the documentation, and the closest I found was

com.rational.test.ft.script.ScriptUtilities.getOperatingSystemVersion() 

which returns OS version info, which might be close, but still not what Daddy is looking for ;O


Solution

  • I didn't find anything in the APIs or in the Windows registry.

    The only way I can think of is to create a custom method and include it in you helper class. You can find the versione in the file C:\IBM\SDP\FunctionalTester\properties\version\IBM_Rational_Functional_Tester.*.*.swtag, change the path to match your installation.

    import java.io.File;
    import java.io.FileInputStream;
    import java.io.FilenameFilter;
    import java.io.IOException;
    
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.ParserConfigurationException;
    
    import org.w3c.dom.Document;
    import org.w3c.dom.Node;
    import org.xml.sax.SAXException;
    import org.xml.sax.SAXParseException;
    
    private final static String RFTVersionFolder = "C:\\IBM\\SDP\\FunctionalTester\\properties\\version";
    
    public static String getRFTVersionWithXML() {
            File versionFolder = new File(RFTVersionFolder);
            File[] versionFile = versionFolder.listFiles( new FilenameFilter() {
                    public boolean accept(File dir, String name) {
                        return (name.endsWith(".swtag"));
                    } } );
    
            Document versionDocument = null;
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    
            try {
                DocumentBuilder builder = factory.newDocumentBuilder();
                versionDocument = builder.parse(new FileInputStream(versionFile[0]));
            } catch (SAXParseException spe) {
                spe.printStackTrace();
            } catch (SAXException sxe) {
                sxe.printStackTrace();
            } catch (ParserConfigurationException pce) {
                pce.printStackTrace();
            } catch (IOException ioe) {
                ioe.printStackTrace();
            }
    
            Node versionNode = versionDocument.getElementsByTagName("ProductVersion").item(0);
    
            return versionNode.getTextContent();
        }
    

    This is a quite expensive method, because it istantiates a DocumentBuilder for XML parsing. As an alternative, load the file content as a String and parse it with a RegExp, use this matching pattern: [0-9]\.[0-9]\.[0-9]

    public static String getRFTVersionWithRegexp() {
        File versionFolder = new File(RFTVersionFolder);
        File[] versionFile = versionFolder.listFiles( new FilenameFilter() {
            public boolean accept(File dir, String name) {
                return (name.endsWith(".swtag"));
            } } );
    
        byte[] buffer = null;
        FileInputStream fin;
        try {
            fin = new FileInputStream(versionFile[0]);
            buffer = new byte[(int) versionFile[0].length()];
            new DataInputStream(fin).readFully(buffer);
            fin.close();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException ioe) {
            ioe.printStackTrace();
        } 
        String versionFileContent = new String(buffer);
        String version = null;
        Regex r = new Regex("[0-9]\\.[0-9]\\.[0-9]", Regex.MATCH_NORMAL);
        if (r.matches(versionFileContent))
            version = r.getMatch();
    
        return version;
    }