How can a Rational Functional Tester script figure out under which version of RFT it executes/was built with?
I digged through the documentation, and the closest I found was
com.rational.test.ft.script.ScriptUtilities.getOperatingSystemVersion()
which returns OS version info, which might be close, but still not what Daddy is looking for ;O
I didn't find anything in the APIs or in the Windows registry.
The only way I can think of is to create a custom method and include it in you helper class.
You can find the versione in the file C:\IBM\SDP\FunctionalTester\properties\version\IBM_Rational_Functional_Tester.*.*.swtag
, change the path to match your installation.
import java.io.File;
import java.io.FileInputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
private final static String RFTVersionFolder = "C:\\IBM\\SDP\\FunctionalTester\\properties\\version";
public static String getRFTVersionWithXML() {
File versionFolder = new File(RFTVersionFolder);
File[] versionFile = versionFolder.listFiles( new FilenameFilter() {
public boolean accept(File dir, String name) {
return (name.endsWith(".swtag"));
} } );
Document versionDocument = null;
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
versionDocument = builder.parse(new FileInputStream(versionFile[0]));
} catch (SAXParseException spe) {
spe.printStackTrace();
} catch (SAXException sxe) {
sxe.printStackTrace();
} catch (ParserConfigurationException pce) {
pce.printStackTrace();
} catch (IOException ioe) {
ioe.printStackTrace();
}
Node versionNode = versionDocument.getElementsByTagName("ProductVersion").item(0);
return versionNode.getTextContent();
}
This is a quite expensive method, because it istantiates a DocumentBuilder for XML parsing. As an alternative, load the file content as a String and parse it with a RegExp, use this matching pattern: [0-9]\.[0-9]\.[0-9]
public static String getRFTVersionWithRegexp() {
File versionFolder = new File(RFTVersionFolder);
File[] versionFile = versionFolder.listFiles( new FilenameFilter() {
public boolean accept(File dir, String name) {
return (name.endsWith(".swtag"));
} } );
byte[] buffer = null;
FileInputStream fin;
try {
fin = new FileInputStream(versionFile[0]);
buffer = new byte[(int) versionFile[0].length()];
new DataInputStream(fin).readFully(buffer);
fin.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException ioe) {
ioe.printStackTrace();
}
String versionFileContent = new String(buffer);
String version = null;
Regex r = new Regex("[0-9]\\.[0-9]\\.[0-9]", Regex.MATCH_NORMAL);
if (r.matches(versionFileContent))
version = r.getMatch();
return version;
}