I have written a C program (which is part of my project) to round off a float value to the given precision specified by the user. The function is something like this
float round_offf (float num, int precision)
What I have done in this program is convert the float number into a string and then processed it.
But is there a way to keep the number as float itself and implement the same.
Eg. num = 4.445 prec = 1 result = 4.4
Of course there is. Very simple:
#include <math.h>
float custom_round(float num, int prec)
{
int trunc = round(num * pow(10, prec));
return (float)trunc / pow(10, prec);
}
Edit: it seems to me that you want this because you think you can't have dynamic precision in a format string. Apparently, you can:
int precision = 3;
double pie = 3.14159265358979323648; // I'm hungry, I need a double pie
printf("Pi equals %.*lf\n", precision, pie);
This prints 3.142
.