pythonprocesslockingmutual-exclusion

Make sure only a single instance of a program is running


Is there a Pythonic way to have only one instance of a program running?

The only reasonable solution I've come up with is trying to run it as a server on some port, then second program trying to bind to same port - fails. But it's not really a great idea, maybe there's something more lightweight than this?

(Take into consideration that program is expected to fail sometimes, i.e. segfault - so things like "lock file" won't work)


Solution

  • The following code should do the job, it is cross-platform and runs on Python 2.4-3.2. I tested it on Windows, OS X and Linux.

    from tendo import singleton
    me = singleton.SingleInstance() # will sys.exit(-1) if other instance is running
    

    The latest code version is available singleton.py. Please file bugs here.

    You can install tend using one of the following methods: