I have the following integral
I wonder how to show that
Below I paste my current attempt in Mathematica.
tmp1 = Sqrt[Sum[(1/i), {i, 1, d}]]
Limit[Integrate[1/Sqrt[(2*\[Pi])] * Exp[-1/2 * z^2], {z, tmp1, Infinity}], d -> Infinity]
Thanks in advance for any pointer or tip.
We can show this by hand. Given we know that the inner function integrates to 1/2 from 0 to infinity we can then say
1/2 = integral from 0 to sqrt(sum( 1/i )) + integral from sqrt(sum(1/i)) to infinity.
Then
1/2 - integral from 0 to sqrt(sum(1/i)) = integral from sqrt(sum(1/i)) to infinity
and since lim d -> infinity of sqrt(sum(1/i)) = infinity we know that the left hand side is zero and this the integral converges to zero.