I made a program in which I am using an array. The problem is the program is not displaying a prompt on the screen which it should. Before I used array in this program, the prompt was working properly. Here is the code:
.data
User: .asciiz "\nEnter 10 number:\n"
Reverse: .asciiz "\nThe reverse order array is:\n"
array: .space 10
.text
main:
la $a0,User
li $v0,4
syscall
li $t1,0
li $t3,0 # counter
la $t0,array
j Input
Input:
li $v0,5
syscall
add $t2,$t3,$t0
sw $v0,0($t2)
addi $t3,$t3,4
beq $t1,9,ReverseInitialization
addi $t1,$t1,1
j Input
ReverseInitialization:
li $t3,36
la $a0,Reverse # NOT DISPLAYING THIS PROMTE
li $v0,4
syscall
j ReverseDisplay
ReverseDisplay:
lw $a0,0($t2)
li $v0,1
syscall
beq $t1,0,Exit
j ReverseDisplay
You're mixing up your datum size again, like you did in a previous question.
You have an array of numbers. There are 10 numbers, according to the first prompt. You're using syscall 5 to read each number. syscall 5 reads an integer into $v0, and as such, the maximum size of the integer is the maximum size of the $v0 register. The size of the register is four bytes, not one. Multiply that by 10, and suddenly your array uses 40 bytes, not 10. So change your array to have a size of 40 instead of 10.
Another main problem is the alignment, pointed out by gusbro in the comments. You're using lw and sw to access the numbers in the array. These instructions operate on words, not bytes. A word is four bytes. Your address needs to therefore be aligned to four bytes. When I run your code as-is, sure enough I get an alignment exception:
Runtime exception at 0x00400030: store address not aligned on word boundary 0x10010031
The address 0x10010031 is not aligned to four bytes because it is not divisible by 4.
As gusbro advised, you need to use the .align directive before your array to force the assembler to store it at a properly aligned address. You actually need an alignment of 4, not 2 I was wrong; align n aligns to 2^n, not n bytes:
.align 2
array: .space 40
Now it works fine.