I've got the following class in TypeScript:
class CallbackTest
{
public myCallback;
public doWork(): void
{
//doing some work...
this.myCallback(); //calling callback
}
}
I am using the class like this:
var test = new CallbackTest();
test.myCallback = () => alert("done");
test.doWork();
The code works, so it displays a messagebox as expected.
My question is: Is there any type I can provide for my class field myCallback
? Right now, the public field myCallback
is of type any
as shown above. How can I define the method signature of the callback? Or can I just set the type to some kind of callback-type? Or can I do nether of these? Do I have to use any
(implicit/explicit)?
I tried something like this, but it did not work (compile-time error):
public myCallback: ();
// or:
public myCallback: function;
I couldn't find any explanation to this online, so I hope you can help me.
I just found something in the TypeScript language specification, it's fairly easy. I was pretty close.
the syntax is the following:
public myCallback: (name: type) => returntype;
In my example, it would be
class CallbackTest
{
public myCallback: () => void;
public doWork(): void
{
//doing some work...
this.myCallback(); //calling callback
}
}
As a type alias:
type MyCallback = (name: type) => returntype;