I'm trying to find the best way of working out whether the machine my code is running on is big-endian or little-endian. I have a solution that works (although I haven't tested it on a big-endian machine) but it seems a bit clunky:
import struct
little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))
This is just comparing a 'native' two-byte pack to a little-endian pack. Is there a prettier way?
The answer is sys module's attribute sys.byteorder
:
An indicator of the native byte order. This will have the value
'big'
on big-endian (most-significant byte first) platforms, and'little'
on little-endian (least-significant byte first) platforms.
Example:
>>> import sys
>>> sys.byteorder
'little'
Of course depending on your machine it may return 'big'
. Your method should certainly work too though.