I am using zk framework 6. I am trying to put my zul pages in /WEB-INF/zul directory. My index.zul file forwards the request to /WEB-INF/zul/login.zul which has a composer LoginComposer. But when I am on login page I want to redirect the user to another page e.g. home.zul. But I am getting 404 error.
Both login.zul and home.zul are in zul directory along with their respective composers.
in loginComposer.java i have the following code to redirect to the home page which is called on a button click.
Execution exec = Executions.getCurrent();
HttpServletResponse response = (HttpServletResponse)exec.getNativeResponse();
response.sendRedirect(response.encodeRedirectURL("/WEB-INF/zul/home.zul")); //assume there is /login
exec.setVoided(true);
I created the project as a zk project from eclipse and i made no changes to web.xml.
please guide me how can i go from here.
Thank in advance.
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>abc</display-name>
<listener>
<description>
Used to cleanup when a session is destroyed</description>
<display-name>ZK Session cleaner</display-name>
<listener-class>org.zkoss.zk.ui.http.HttpSessionListener</listener-class>
</listener>
<servlet>
<description>
The ZK loader for ZUML pages</description>
<servlet-name>zkLoader</servlet-name>
<servlet-class>org.zkoss.zk.ui.http.DHtmlLayoutServlet</servlet-class>
<init-param>
<param-name>update-uri</param-name>
<param-value>/zkau</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<description>
The asynchronous update engine for ZK</description>
<servlet-name>auEngine</servlet-name>
<servlet-class>org.zkoss.zk.au.http.DHtmlUpdateServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>zkLoader</servlet-name>
<url-pattern>*.zul</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>zkLoader</servlet-name>
<url-pattern>*.zhtml</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>auEngine</servlet-name>
<url-pattern>/zkau/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
<welcome-file>index.zul</welcome-file>
</welcome-file-list>
</web-app>
zk.xml
<?xml version="1.0" encoding="UTF-8"?>
<!--
Created by ZK Studio
-->
<zk>
<device-config>
<device-type>ajax</device-type>
<timeout-uri>/timeout.zul</timeout-uri><!-- An empty URL can cause the browser to reload the same URL -->
</device-config>
</zk>
LoginComposer.java
public class LoginComposer extends SelectorComposer<Component>{
private static final long serialVersionUID = -1657004425904043268L;
@Wire
private Button buttontestButton;
@Listen("onClick = #testButton")
public void cancelButton(){
Executions.sendRedirect("/WEB-INF/zul/home.zul");
}
}
I looked around and found a german site tht explains, that the spec
of java-servlet define the WEB-INF folder as not client accessable,
cos it contains data as classes that never should be accessed from outside the server.
You should better use Executions.sendRedirect(java.lang.String uri)
to redirect by a button click with server-side action needed.
If you just want to redirect, set the buttons href.
It should look like
Executions.sendRedirect("/zul/home.zul");
or in java:
myButton.setHref("/zul/home.zul");
in zul:
<button ... href="/zul/home.zul" ...>
I could write much, but the best would be to say, if you
If you still have 404 and can't figure them out, please post your
configuration files or classes.