I would like to test the example of the use of the nonlocal statement specified in the answer on this question:
def outer():
x = 1
def inner():
nonlocal x
x = 2
print("inner:", x)
inner()
print("outer:", x)
but when I try to load this code, I always get a syntax error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "t.py", line 4
nonlocal x
^
SyntaxError: invalid syntax
Does anybody know what I am doing wrong here (I get the syntax error for every example that I use, containing nonlocal).
nonlocal only works in Python 3; it is a new addition to the language.
In Python 2 it'll raise a syntax error; python sees nonlocal as part of an expression instead of a statement.
This specific example works just fine when you actually use the correct Python version:
$ python3.3
Python 3.3.0 (default, Sep 29 2012, 08:16:08)
[GCC 4.2.1 Compatible Apple Clang 3.1 (tags/Apple/clang-318.0.58)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> def outer():
... x = 1
... def inner():
... nonlocal x
... x = 2
... print("inner:", x)
... inner()
... print("outer:", x)
...