In this piece of code, why does using for
result in no StopIteration
or is the for
loop trapping all exceptions and then silently exiting?
In which case, why do we have the extraneous return
?? Or is the
raise StopIteration
caused by: return None
?
#!/usr/bin/python3.1
def countdown(n):
print("counting down")
while n >= 9:
yield n
n -= 1
return
for x in countdown(10):
print(x)
c = countdown(10)
next(c)
next(c)
next(c)
Assuming StopIteration
is being triggered by: return None
.
When is GeneratorExit
generated?
def countdown(n):
print("Counting down from %d" % n)
try:
while n > 0:
yield n
n = n - 1
except GeneratorExit:
print("Only made it to %d" % n)
If I manually do a:
c = countdown(10)
c.close() #generates GeneratorExit??
In which case why don't I see a traceback?
The for
loop listens for StopIteration
explicitly.
The purpose of the for
statement is to loop over the sequence provided by an iterator and the exception is used to signal that the iterator is now done; for
doesn't catch other exceptions raised by the object being iterated over, just that one.
That's because StopIteration
is the normal, expected signal to tell whomever is iterating that there is nothing more to be produced.
A generator function is a special kind of iterator; it indeed raises StopIteration
when the function is done (i.e. when it returns, so yes, return None
raises StopIteration
). It is a requirement of iterators; they must raise StopIteration
when they are done; in fact, once a StopIteration
has been raised, attempting to get another element from them (through next()
, or calling the .next()
(py 2) or .__next__()
(py 3) method on the iterator) must always raise StopIteration
again.
GeneratorExit
is an exception to communicate in the other direction. You are explicitly closing a generator with a yield
expression, and the way Python communicates that closure to the generator is by raising GeneratorExit
inside of that function. You explicitly catch that exception inside of countdown
, its purpose is to let a generator clean up resources as needed when closing.
A GeneratorExit
is not propagated to the caller; see the generator.close()
documentation.