Is there any way to efficiently do this, perhaps through toBuffer or to methods? My real problem is I'm building a List off a parser, as follows:
lazy val nodes: Parser[List[Node]] = phrase(( nodeA | nodeB | nodeC).*)
But after building it, I want it to be a buffer instead - I'm just not sure how to build a buffer straight from the parser.
to indeed does the trick, and it is pretty trivial to use:
scala> val l = List(1,2,3)
l: List[Int] = List(1, 2, 3)
scala> l.to[ListBuffer]
res1: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3)
Works in scala 2.10.x
For scala 2.9.x, you can do:
scala> ListBuffer.empty ++= l
res1: scala.collection.mutable.ListBuffer[Int] = ListBuffer(1, 2, 3)