I'd like to take the perspective transform matrix returned from OpenCV's findHomography function and convert it (either in C++ or Objective-C) to iOS' CATransform3D. I'd like them to be as close as possible in terms of accurately reproducing the "warp" effect on the Core Graphics side. Example code would really be appreciated!
From iOS' CATransform3D.h:
/* Homogeneous three-dimensional transforms. */
struct CATransform3D
{
CGFloat m11, m12, m13, m14;
CGFloat m21, m22, m23, m24;
CGFloat m31, m32, m33, m34;
CGFloat m41, m42, m43, m44;
};
Similar questions:
Disclaimer
I have never tried this so take it with a grain of salt.
CATRansform3D is a 4x4 matrix which operates on a 3 dimensional homogeneous vector (4x1) to produce another vector of the same type. I am assuming that when rendered, objects described by a 4x1 vector have each element divided by the 4th element and the 3rd element is used only to determine which objects appear on top of which. Assuming this is correct...
Reasoning
The 3x3 matrix returned by findHomography operates on a 2 dimensional homogeneous vector. That process can be thought of in 4 steps
You need this process to be replicated in a 4x4 vector in which I am assuming the 3rd element in the resulting vector is meaningless for your purposes.
Solution
Construct your matrix like this (H is your homography matrix)
[H(0,0), H(0,1), 0, H(0,2),
H(1,0), H(1,1), 0, H(1,2),
0, 0, 1, 0
H(2,0), H(2,1), 0, H(2,2)]
This clearly satisfies 1,2 and 3. 4 is satisfied because the homogeneous element is always the last one. That is why the "homogeneous row" if you will had to get bumped down one line. The 1 on the 3rd row is to let the z component of the vector pass through unmolested.
All of the above is done in row major notation (like openCV) to try to keep things from being confusing. You can look at Tommy's answer to see how the conversion to column major looks (you basically just transpose it). Note however that at the moment Tommy and I disagree about how to construct the matrix.