What i want to do is swapping two HTML DOM nodes.
Let's take the following HTML list and the swap button below:
<ul class="center-text">
<li>0</li>
<li>1</li>
<li>2</li>
</ul>
<form class="center-text">
<button id="swapButton">Swap</button>
</form>
And here is my JS code:
// the "ready" method is the only jQuery method used in the code
$(document).ready(function(){
document.getElementById("swapButton").onclick = function() {
var ul = document.getElementsByTagName("ul")[0];
// pseudo-swapping: insert "child2" before "child0"
// (indexes are 1 and 5 because of the TextNodes between list nodes)
ul.insertBefore(ul.childNodes.item(5), ul.childNodes.item(1));
}
});
So here is what happens when clicking the swap button:
The items are swaped indeed. But Somehow after (let's say 1/4) seconds they are restored to their original position, i.e. swaped back automatically.
My question is: WHY?
PS: the code is merely for educational purposes and i only try to understand what's going on behind the doors, so please do NOT post any alternative jQuery method.
$(document).ready(function(){
document.getElementById("swapButton").onclick = function(e) {
e.preventDefault();
var ul = document.getElementsByTagName("ul")[0];
ul.insertBefore(ul.childNodes.item(5), ul.childNodes.item(1));
}
});
This is because button redirects the page to same page. And reverts all. You need to prevent the default behaviour of button.