[SOLVED] Looping through the content of a file in Bash

Looping through the content of a file in Bash

How do I iterate through each line of a text file with Bash?

With this script:

echo "Start!"
for p in (peptides.txt)
do
    echo "${p}"
done

I get this output on the screen:

Start!
./runPep.sh: line 3: syntax error near unexpected token `('
./runPep.sh: line 3: `for p in (peptides.txt)'

(Later I want to do something more complicated with $p than just output to the screen.)

The environment variable SHELL is (from env):

SHELL=/bin/bash

/bin/bash --version output:

GNU bash, version 3.1.17(1)-release (x86_64-suse-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.

cat /proc/version output:

Linux version 2.6.18.2-34-default (geeko@buildhost) (gcc version 4.1.2 20061115 (prerelease) (SUSE Linux)) #1 SMP Mon Nov 27 11:46:27 UTC 2006

The file peptides.txt contains:

RKEKNVQ
IPKKLLQK
QYFHQLEKMNVK
IPKKLLQK
GDLSTALEVAIDCYEK
QYFHQLEKMNVKIPENIYR
RKEKNVQ
VLAKHGKLQDAIN
ILGFMK
LEDVALQILL

Solution

One way to do it is:

while read p; do
  echo "$p"
done <peptides.txt

As pointed out in the comments, this has the side effects of trimming leading whitespace, interpreting backslash sequences, and skipping the last line if it's missing a terminating linefeed. If these are concerns, you can do:

while IFS="" read -r p || [ -n "$p" ]
do
  printf '%s\n' "$p"
done < peptides.txt

Exceptionally, if the loop body may read from standard input, you can open the file using a different file descriptor:

while read -u 10 p; do
  ...
done 10<peptides.txt

Here, 10 is just an arbitrary number (different from 0, 1, 2).