mavenservletsparametersweb.xml

How to replace a value in web.xml with a Maven property?


I have a Maven project that downloads some test files into its build directory ./target/files. These files should then be available to a servlet, which I can easily achieve by hardcoding the full path as an <init-param> of the servlet:

<servlet>
    <servlet-name>TestServlet</servlet-name>
    <servlet-class>my.package.TestServlet</servlet-class>
    <init-param>
        <param-name>filepath</param-name>
        <param-value>/home/user/testproject/target/files</param-value>
    </init-param>
</servlet>

How can I avoid hardcoding the full path and use a dynamic parameter replacement instead? I tried the following, but it did not work:

<param-value>${project.build.directory}/files</param-value>

Solution

  • Add to your pom section:

    <plugin>
        <groupId>org.apache.maven.plugins</groupId>
        <artifactId>maven-war-plugin</artifactId>
        <configuration>
            <webResources>
                <resource>
                    <filtering>true</filtering>
                    <directory>src/main/webapp</directory>
                    <includes>
                        <include>**/web.xml</include>
                    </includes>
                </resource>
            </webResources>
        </configuration>
    </plugin>
    

    See Maven: Customize web.xml of web-app project for more details