pythonpandascountgroup-bydistinct

Pandas 'count(distinct)' equivalent

I am using Pandas as a database substitute as I have multiple databases (Oracle, SQL Server, etc.), and I am unable to make a sequence of commands to a SQL equivalent.

I have a table loaded in a DataFrame with some columns:

YEARMONTH, CLIENTCODE, SIZE, etc., etc.

In SQL, to count the amount of different clients per year would be:

SELECT count(distinct CLIENTCODE) FROM table GROUP BY YEARMONTH;

And the result would be

201301    5000
201302    13245

How can I do that in Pandas?

Solution

  • I believe this is what you want:

    table.groupby('YEARMONTH').CLIENTCODE.nunique()

    Example:

    In [2]: table
Out[2]: 
   CLIENTCODE  YEARMONTH
0           1     201301
1           1     201301
2           2     201301
3           1     201302
4           2     201302
5           2     201302
6           3     201302

In [3]: table.groupby('YEARMONTH').CLIENTCODE.nunique()
Out[3]: 
YEARMONTH
201301       2
201302       3