c++templatesc++11type-traits

How do I use std::is_integral<> to select an implementation?


I'm trying to return an int64_t if std::is_integral<>::value is true.

Otherwise, I would like to call to_int64t() on the object.

My attempt below is failing because partial specialisation of function templates are not allowed.

CODE

#include <type_traits>
#include <cstdint>

template<class T,bool is_integral_type>
int64_t to_int64t( const T& t )
{
        return t;
}

template<class T>
int64_t to_int64t<T,std::is_integral<T>::value>( const T& t )
{
        return t;
}

template<class T>
int64_t to_int64t<T,!std::is_integral<T>::value>( const T& t )
{
        return t.to_int64t();
}

int main()
{
        int64_t i = 64;
        auto x = to_int64t( i );
}

Solution

  • Function templates cannot be partially specialized and, in general, it is not a good idea to use function template specialization.

    One way to achieve what you want is to use a technique called tag dispatching, which basically consists in providing a forwarder function that selects the right overload based on the value of an extra dummy argument:

    #include <type_traits>
    #include <cstdint>
    
    template<class T>
    int64_t to_int64t( const T& t, std::true_type )
    {
        return t;
    }
    
    template<class T>
    int64_t to_int64t( const T& t, std::false_type )
    {
        return t.to_int64t();
    }
    
    template<class T>
    int64_t to_int64t( const T& t )
    {
        return to_int64t(t, std::is_integral<T>());
    }
    
    int main()
    {
        int64_t i = 64;
        auto x = to_int64t( i );
    }
    

    Another possibility is to use the classical SFINAE technique based on std::enable_if. This is how that could look like (notice that, since C++11, default template arguments on function templates are allowed):

    #include <type_traits>
    #include <cstdint>
    
    template<class T, typename std::enable_if<
        std::is_integral<T>::value>::type* = nullptr>
    int64_t to_int64t( const T& t )
    {
        return t;
    }
    
    template<class T, typename std::enable_if<
        !std::is_integral<T>::value>::type* = nullptr>
    int64_t to_int64t( const T& t )
    {
        return t.to_int64t();
    }
    
    int main()
    {
        int64_t i = 64;
        auto x = to_int64t( i );
    }
    

    Yet another possibility, although more verbose, is to define helper class templates (which can be partially specialized) in a detail namespace and provide a global forwarder - I would not use this technique for this use case, but I am showing it because it might come handy in related design situations:

    #include <type_traits>
    #include <cstdint>
    
    namespace detail
    {
        template<class T, bool = std::is_integral<T>::value>
        struct helper { };
    
        template<class T>
        struct helper<T, true>
        {
            static int64_t to_int64t( const T& t )
            {
                return t;
            }
        };
    
        template<class T>
        struct helper<T, false>
        {
            static int64_t to_int64t( const T& t )
            {
                return t.to_int64t();
            }
        };
    }
    
    template<class T>
    int64_t to_int64t( const T& t )
    {
        return detail::helper<T>::to_int64t(t);
    }
    
    int main()
    {
        int64_t i = 64;
        auto x = to_int64t( i );
    }