Google maps v3 - Draw a polygon to show photo take angle

I am displaying in google maps (v3) markers with the position where the photograph was taken and position of the subject and tracing a line to show direction in which photo was taken. I have also calculated the distance and the angle from camera position.

What I am trying now is to show the view from camera with a triangle that opens, lets say 30 degrees toward the subject. Seem to me is a third grade math, but can't figure out after 25 years, I know how to draw the polygon/triangle but not really how to calculate the points at subject's distance about 30 degrees in both directions, of course taking in mind the heading angle.

Almost there...

Used the formula Red answered below to create a function (found I needed to convert: lat1, lon1 and bearing to radians before the math.
I call this function each time a marker changes to calculate again pos1 and pos2 of the triangle and change the paths to redraw it.

Thing now is that triangle shows up but facing all kind of directions but the proper one.

Question now is:

Google return the heading in degrees negative to West and positive to East (-180/180) and seems that the formula need the bearing (heading) in 360 degress? Right now function CameraView(75) display correctly but I am passing the angle as 75 degrees instead of 15 degrees (to have 15 degrees view left, and 15 to right).

function getVertex(brng) {

var R = 6366.707;
var d = parseFloat( getObj('GPSDestDistance').value ) * 1.5  //distance on form field

//position of Camera
var lat1 = deg2rad( markerCam.getPosition().lat() )
var lon1 = deg2rad( markerCam.getPosition().lng() )

var lat2 = Math.asin( Math.sin(lat1) * Math.cos(d/R) + Math.cos(lat1) * Math.sin(d/R) * Math.cos(brng) );
var lon2 = lon1 + Math.atan2( Math.sin(brng) * Math.sin(d/R) * Math.cos(lat1), Math.cos(d/R) - Math.sin(lat1) * Math.sin(lat2) );

lat2 = rad2deg( lat2 )
lon2 = rad2deg( lon2 )

var pos = new google.maps.LatLng(lat2, lon2)
return pos;
}
function CameraView(angle) {
var brng = deg2rad( parseFloat( getObj('GPSDestBearing').value ) );  //get heading from form
if(brng<0){
    //brng = Math.round(-brng / 360 + 180)
    }
var pos1 = markerCam.getPosition();
var pos2 = getVertex(brng - angle);
var pos3 = getVertex(brng + angle);
var paths = [ pos1, pos2, pos3 ];
poly.setPath(paths);
}

function deg2rad(x)     { return x * (Math.PI / 180); }
function rad2deg(x)     { return x * (180 / Math.PI); }

The formula to get an endpoint latitude and longitude (lat 2,lon2) (in radians) from a starting location (lat1,lon1) (also in radians), range (d), radius of the Earth (R) and bearing (brng) is:

var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) );
var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));

Your start point will be one of the points of the triangle polygon. The other two can be found using this code snippet, putting in your bearing +/- 15 degrees (for the 30 degree triangle example) and a range that depends entirely on how big you want the triangle.