scalaextractorunapply

How to use extractor in polymorphic unapply?


I don't really get this little thingy. I have an abstract class Box with several sub-classes for different types. For example

abstract class Box
class StringBox(val sValue : String) extends Box

The apply method in the companion object for Box is simple:

object Box{
    def apply(s: String)  = new StringBox(s)
    def apply(b: Boolean) = new BooleanBox(b)
    def apply(d: Double)  = new DoubleBox(d)
}

so I can write

    val sb = Box("StringBox)

Okay, writing unapply makes some trouble. My first idea was to use pattern matching on the type, like this this:

def unapply(b: Box) = b match {
  case sb: StringBox => Some(sb.sValue)
  case bb: BooleanBox => Some(bb.bValue)
  case db: DoubleBox => Some(db.dValue)
  case _ => None

}

Which simply doesn't work because of type erasures.

Second attempt was a generic Box[T] with type T and an abstract type member re-defined in each sub classes. For instance:

 abstract class Box[T] {def value : T}
 class StringBox(val sValue : String)  extends Box[String] { 
   override def value : String = sValue
 }

Consequently, I can re write my unapply as:

def unapply[T](b: Box[T]) = b match {
  case sb: Box[String]  => Some(sb.value)
  case bb: Box[Boolean] => Some(bb.value)
  case db: Box[Double]  => Some(db.value)
  case _ => None

Unfortunately, this doesn't work either. So I guess the explicit type reference in Box[String] gets erased as well so I need to use a type manifest instead. Maybe something like:

def unapply[T](b: Box[_])(implicit target: Manifest[T]): Option[T] = {

   if(b.value ==  target) Some(b.value.asInstanceOf[T])
   else None 
}

This code compiles (2.10) but still does not the desired implicit conversion. Why?

Simple question, is there a way to do value extraction without using reflection or a manifest?

What really boggles me is the question if there is a simple(r) way to combine polymorphism and pattern matching? If not, are there other ways in Scala to accomplish a similar effect?

Any idea or suggestions?

Thank you very much.


Solution

  • Prolly you can try this.. :)

      abstract class Box[T](val v: T)
    
      object Box {
        def apply(s: String) = new StringBox(s)
        def apply(b: Boolean) = new BooleanBox(b)
        def apply(d: Double) = new DoubleBox(d)
    
      }
    
      class StringBox(sValue: String) extends Box(sValue)
      object StringBox {
        def unapply(b: StringBox) = Some(b.v)
      }
    
      class BooleanBox(sValue: Boolean) extends Box(sValue)
      object BooleanBox {
        def unapply(b: BooleanBox) = Some(b.v)
      }
    
      class DoubleBox(sValue: Double) extends Box(sValue)
      object DoubleBox {
        def unapply(b: DoubleBox) = Some(b.v)
      }
    

    You can use it as --

      def useCase[T](box: Box[T]) = box match {
        case StringBox("StringBoxxx") => "I found the StringBox!"
        case StringBox(s) => "Some other StringBox"
        case BooleanBox(b) => {
                 if (b)  "Omg! its true BooleanBox !"
                 else "its false BooleanBox :("
                 }
        case DoubleBox(x) => {
                    if (x > 3.14)  "DoubleBox greater than pie !"
                    else if (x == 3.14) "DoubleBox with a pie !"
                    else "DoubleBox less than a pie !"
        }
        case _ => "What is it yaa ?"
      }                                             
    
      useCase(Box("StringBoxxx")) //> res0: String = I found the StringBox!
      useCase(Box("Whatever !"))  //> res1: String = Some other StringBox
      useCase(Box(true))          //> res2: String = Omg! its true BooleanBox !
      useCase(Box(false))         //> res3: String = its false BooleanBox :(
      useCase(Box(4))             //> res4: String = DoubleBox greater than pie !
      useCase(Box(3.14))          //> res5: String = DoubleBox with a pie !
      useCase(Box(2))             //> res6: String = DoubleBox less than a pie !