Write a branchless function that returns 0, 1, or 2 if the difference between two signed integers is zero, negative, or positive.
Here's a version with branching:
int Compare(int x, int y)
{
int diff = x - y;
if (diff == 0)
return 0;
else if (diff < 0)
return 1;
else
return 2;
}
Here's a version that may be faster depending on compiler and processor:
int Compare(int x, int y)
{
int diff = x - y;
return diff == 0 ? 0 : (diff < 0 ? 1 : 2);
}
Can you come up with a faster one without branches?
SUMMARY
The 10 solutions I benchmarked had similar performance. The actual numbers and winner varied depending on compiler (icc/gcc), compiler options (e.g., -O3, -march=nocona, -fast, -xHost), and machine. Canon's solution performed well in many benchmark runs, but again the performance advantage was slight. I was surprised that in some cases some solutions were slower than the naive solution with branches.
int Compare(int x, int y) {
return (x < y) + (y < x) << 1;
}
Edit: Bitwise only? Guess < and > don't count, then?
int Compare(int x, int y) {
int diff = x - y;
return (!!diff) | (!!(diff & 0x80000000) << 1);
}
But there's that pesky -
.
Edit: Shift the other way around.
Meh, just to try again:
int Compare(int x, int y) {
int diff = y - x;
return (!!diff) << ((diff >> 31) & 1);
}
But I'm guessing there's no standard ASM instruction for !!
. Also, the <<
can be replaced with +
, depending on which is faster...
Bit twiddling is fun!
Hmm, I just learned about setnz
.
I haven't checked the assembler output (but I did test it a bit this time), and with a bit of luck it could save a whole instruction!:
subl %edi, %esi
setnz %eax
sarl $31, %esi
andl $1, %esi
sarl %eax, %esi
mov %esi, %eax
ret
Rambling is fun.
I need sleep.