If I want to construct a std::string
with a line like:
std::string my_string("a\0b");
Where I want to have three characters in the resulting string (a, null, b), I only get one. What is the proper syntax?
we have been able to create literal std::string
#include <iostream>
#include <string>
int main()
{
using namespace std::string_literals;
std::string s = "pl-\0-op"s; // <- Notice the "s" at the end
// This is a std::string literal not
// a C-String literal.
std::cout << s << "\n";
}
The problem is the std::string
constructor that takes a const char*
assumes the input is a C-string. C-strings are \0
terminated and thus parsing stops when it reaches the \0
character.
To compensate for this, you need to use the constructor that builds the string from a char array (not a C-String). This takes two parameters - a pointer to the array and a length:
std::string x("pq\0rs"); // Two characters because input assumed to be C-String
std::string x("pq\0rs",5); // 5 Characters as the input is now a char array with 5 characters.
Note: C++ std::string
is NOT \0
-terminated (as suggested in other posts). However, you can extract a pointer to an internal buffer that contains a C-String with the method c_str()
.
Also check out Doug T's answer below about using a vector<char>
.
Also check out RiaD for a C++14 solution.