I'm trying to print my key/value pairs of data in my CodeIgniter view. However, I'm getting the following error. What I'm I doing wrong?
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: data
Filename: views/search_page2.php
Line Number: 8
application/controller/search.php
// ...
$this->load->library('/twitter/TwitterAPIExchange', $settings);
$url = 'https://api.twitter.com/1.1/followers/ids.json';
$getfield = '?username=johndoe';
$requestMethod = 'GET';
$twitter = new TwitterAPIExchange($settings);
$data['url'] = $url;
$data['getfield'] = $getfield;
$data['requestMethod'] = $requestMethod;
$this->load->view('search_page2', $data);
// ...
application/views/search_page2.php
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Twitter Test</title>
</head>
<body>
<?php print_r($data); ?>
<?php foreach ($data as $key => $value): ?>
<h2><?php echo $key . ' ' . $value . '<br />'; ?></h2>
<?php endforeach ?>
</body>
</html>
to get the data array accessible in the view do like
$data['url'] = $url;
$data['getfield'] = $getfield;
$data['requestMethod'] = $requestMethod;
$data['data'] = $data;
$this->load->view('search_page2', $data);
else only the variables with names as its keys will be available in the view not the data variable we pass.
this is in response to your comment to juan's answer Actually if you are trying make it working in the other way proposed.
controller code will be having no change from the code you posted.
$data['url'] = $url;
$data['getfield'] = $getfield;
$data['requestMethod'] = $requestMethod;
$this->load->view('search_page2', $data);
but in the view code you will need to just do.
<h2>url <?PHP echo $url; ?><br /></h2>
<h2>getfield <?PHP echo $getfield; ?><br /></h2>
<h2>requestMethod <?PHP echo $requestMethod; ?><br /></h2>
instead of the foreach loop as your keys in $data are already available as respective named variables inside the view.