[SOLVED] python regex, match in multiline, but still want to get the line number

python regex, match in multiline, but still want to get the line number

I have lots of log files, and want to search some patterns using multiline, but in order to locate matched string easily, I still want to see the line number for matched area.

Any good suggestion. (code sample is copied)

string="""
####1
ttteest
####1
ttttteeeestt

####2

ttest
####2
"""

import re
pattern = '.*?####(.*?)####'
matches= re.compile(pattern, re.MULTILINE|re.DOTALL).findall(string)
for item in matches:
    print "lineno: ?", "matched: ", item

[UPDATE] the lineno is the actual line number

So the output I want looks like:

    lineno: 1, 1
    ttteest
    lineno: 6, 2
    ttttteeeestt

Solution

You can store the line numbers before hand only and afterwards look for it.

import re

string="""
####1
ttteest
####1
ttttteeeestt

####2

ttest
####2
"""

end='.*\n'
line=[]
for m in re.finditer(end, string):
    line.append(m.end())

pattern = '.*?####(.*?)####'
match=re.compile(pattern, re.MULTILINE|re.DOTALL)
for m in re.finditer(match, string):
    print 'lineno :%d, %s' %(next(i for i in range(len(line)) if line[i]>m.start(1)), m.group(1))