phpmysqlcodeigniterdatabase-abstraction

get value single value from array var that stores result of query php

I have a query that stores result of query like

$this->load->model('person/person_model');
$data['result'] = $this->person_model->get('tbl_person', array('id_person' => $some_key),TRUE);

this will return all the fields of person with $some_key (id,name,email...) Then I need to pass $data but before I would like to use name and email of that result

so

$this->load->model('person/other_person_job_model');
$status= $this->other_person_job_model->get('tbl_other_person',array('name'=> ?  ),TRUE);

Then I could use $status['name'] or $status['email'] What should I put instead of ? in the example above? Should I use $data['result']['name'] or something like that? the get function is:

function get($table,$where=array(),$single=FALSE) {
        $q = $this->db->get_where($table,$where);
        $result = $q->result_array();
        if($single) {
            return $result[0];
        }
        return $result;
    }
Solution

  • you could use variable, like:

    $this->load->model('person/person_model');
$result = $this->person_model->get('tbl_person', array('id_person' => $some_key),TRUE);
$data['name'] = $result->name;
$data['result'] = $result;
//and
$this->load->model('person/other_person_job_model');
$status= $this->other_person_job_model->get('tbl_other_person',array('name'=> $result->name  ),TRUE);