How do I remove even numbers from an ArrayList?

I have to create a method which has an ArrayList; I need to remove even numbers from this ArrayList. I have written code for that, but there is a logical error which I couldn't identify.

Here is my code:

static void sortList(){

   List <Integer> number=new ArrayList <Integer>();

   number.add(11);
   number.add(45);
   number.add(12);
   number.add(32);
   number.add(36);

   System.out.println("Unsorted List: "+number);
  
   for (int i=0;i<number.size();i++){      
       int even=number.get(i)%2;       
        if (even==0){
            System.out.println("This is Even Number:"+ number.get(i));
            number.remove(i);
        }    
    }

    Collections.sort(number);
    System.out.println("Sorted List: "+number);

 }

The output of the code is:

Unsorted List: [11, 45, 12, 32, 36]
This is Even Number:12
This is Even Number:36
Sorted List: [11, 32, 45]

I am wondering that why 32 is not caught as an even number as it is an even number; I tested then by using different even numbers at same position, but the result is same. Why at index(3), is it happening that any even number couldn't be catch. I am really wondering why. So please any one can help me out for this, and is there any other better way to implement this solution?

Thanks

Use an Iterator. It has an remove() method which you need.

List<Integer> numbers = new ArrayList<Integer>();

numbers.add(11);
numbers.add(45);
numbers.add(12);
numbers.add(32);
numbers.add(36);

System.out.println("Unsorted List: " + numbers);

for (Iterator<Integer> iterator = numbers.iterator(); iterator.hasNext();) {
    Integer number = iterator.next();
    if (number % 2 == 0) {
        System.out.println("This is Even Number: " + number);
        iterator.remove();
    }

}

Collections.sort(numbers);
System.out.println("Sorted List: " + numbers);