I'd like to construct an absolute path in python, while at the same time staying fairly oblivious of things like path-separator.
edit0: for instance there is a directory on the root of my filesystem /etc/init.d
(or C:\etc\init.d
on w32), and I want to construct this only from the elements etc
and init.d
(on w32, I probably also need a disk-ID, like C:
)
In order to not having to worry about path-separators, os.join.path()
is obviously the tool of choice. But it seems that this will only ever create relative paths:
print("MYPATH: %s" % (os.path.join('etc', 'init.d'),)
MYPATH: etc/init.d
Adding a dummy first-element (e.g. ''
) doesn't help anything:
print("MYPATH: %s" % (os.path.join('', 'etc', 'init.d'),)
MYPATH: etc/init.d
Making the first element absolute obviously helps, but this kind of defeats the idea of using os.path.join()
print("MYPATH: %s" % (os.path.join('/etc', 'init.d'),)
MYPATH: /etc/init.d
edit1: using os.path.abspath()
will only try to convert a relative path into an absolute path.
e.g. consider running the following in the working directory /home/foo
:
print("MYPATH: %s" % (os.path.abspath(os.path.join('etc', 'init.d')),)
MYPATH: /home/foo/etc/init.d
So, what is the standard cross-platform way to "root" a path?
root = ??? # <--
print("MYPATH: %s" % (os.path.join(root, 'etc', 'init.d'),)
MYPATH: /etc/init.d
edit2: the question really boils down to: since the leading slash in /etc/init.d
makes this path an absolute path, is there a way to construct this leading slash programmatically?
(I do not want to make assumptions that a leading slash indicates an absolute path)
so the solution i came up with, is to construct the root of the filesystem by following a given file to it's root:
def getRoot(file=None):
if file is None:
file='.'
me=os.path.abspath(file)
drive,path=os.path.splitdrive(me)
while 1:
path,folder=os.path.split(path)
if not folder:
break
return drive+path
os.path.join(getRoot(), 'etc', 'init.d')