I am using system.io.packaging.package to create a package containing some files. Purpose is to create an import/export functionnality.
I create the package like that :
// Create the compressed file.
using (FileStream outFile = File.Create(this.packageName))
{
using (Package Compress = Package.Open(outFile, FileMode.Create))
{
foreach (string file in Directory.GetFiles(Path.GetDirectoryName(this.packageName)))
{
FileInfo fi = new FileInfo(file);
// Prevent compressing hidden and already compressed files.
if ((File.GetAttributes(fi.FullName) & FileAttributes.Hidden) != FileAttributes.Hidden & fi.Extension != ".gz")
{
PackagePart packagePartDocument;
if (fi.Extension == ".xml")
{
packagePartDocument = Compress.CreatePart(PackUriHelper.CreatePartUri(new Uri(@"/" + Path.GetFileName(file), UriKind.Relative)), System.Net.Mime.MediaTypeNames.Text.Xml);
}
else
{
packagePartDocument = Compress.CreatePart(PackUriHelper.CreatePartUri(new Uri(@"/" + Path.GetFileName(file), UriKind.Relative)), System.Net.Mime.MediaTypeNames.Text.Plain);
}
using (FileStream inFile = fi.OpenRead())
{
inFile.CopyTo(packagePartDocument.GetStream());
}
Compress.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, fi.FullName);
}
}
}
}
and I read it like that :
using (Package zip = Package.Open(PackageStream, FileMode.Open, FileAccess.Read, FileShare.None))
{
Directory.CreateDirectory(Path.Combine(App.Configuration.TempDirectory, this.packageName.Split('.')[0]));
foreach (PackagePart file in zip.GetParts())
{
string fileName = Path.Combine(App.Configuration.TempDirectory, this.packageName.Split('.')[0], file.Uri.ToString().TrimStart('/'));
using (FileStream fileStream = new FileStream(fileName, FileMode.Create))
{
file.GetStream().CopyTo(fileStream);
}
}
}
My issue occurs when Package try to open the file
Package zip = Package.Open(PackageStream, FileMode.Open, FileAccess.Read, FileShare.None)
I have an error "File contains corrupted data"
I have done many tests over and over and I don't understand...
EDIT : The same code is working with an console applciation but not in a web application.
Finally I found my mistake :
When I return this generated package I return the package but the entire web page too.
Response.AddHeader("content-disposition", "attachment; filename=" + export.PackageName);
Response.ContentType = "application/octet-stream";
Response.WriteFile(export.PackageFullName);
So I corrected it by
Response.Clear();
Response.ClearHeaders();
Response.ClearContent();
Response.AddHeader("content-disposition", "attachment; filename=" + export.PackageName);
Response.ContentType = "application/octet-stream";
Response.WriteFile(export.PackageFullName);
Response.Flush();
Response.End();
It works :)