I have been using css selectors as div and span till now while using Selenium WebDrivers with Ruby for testing.
However I have some dd and xmlns:dd attributes as well. Is it possible to have a css selector for this as well.
HTML Code:
<div class="class1 class2 class3 class4" style="padding: 4px;" id="_c04a6325-5316-4177-980f-38484eb27730">
<span class="class5" style="font-weight: bold; text-decoration: underline;">Month</span>
<div class="class6" dd:contenttype="Month" dd:referenceuuid="1446A201-FD91-4A82-B645- 306DC948DC48" id="_3d510b04-8a5a-4bf9-bc7a-8efd55f9ca48">
<div xmlns:dd="Week" class="class7 class8" dd:entityid="1457893" dd:contenttype="Monday" id="_7480bbe4-bbf0-4a54-8994-ae773b418470">Breakfast
</div>
</div>
</span>
</div>
What I presently do:
$driver.find_elements(:css, 'div.class7.class8')
What I want to do:
Something like this to use the data in dd:contenttype and/or xmlns:dd to find an element
$driver.find_elements(:css, 'div.dd:contenttype="Monday"') OR
$driver.find_elements(:css, 'div.xmlns:dd="Week"')
Is the possible to find and element using dd:contenttype and/or xmlns:dd??
use $driver.find_elements(:css, 'div[dd\\:contenttype="Monday"]')
for more information you can take a look on http://sauceio.com/index.php/2010/01/selenium-totw-css-selectors-in-selenium-demystified/