Basically, I have a multidimensional array, and I need to check whether or not it is simply empty, or not.
I currently have an if
statement trying to do this with:
if(!empty($csv_array))
{
//My code goes here if the array is not empty
}
Although, that if statement
is being activated whether the multidimensional array is empty or not.
This is what the array looks like when empty:
Array
(
[0] => Array
(
)
)
This is what the array looks like when it has a few elements in it:
Array
(
[0] => Array
(
)
[1] => Array
(
[1] => question1
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
[2] => Array
(
[1] => question2
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
[3] => Array
(
[1] => question3
[2] => answer1
[3] => answer2
[4] => answer3
[5] => answer4
)
)
My array elements always start at 1, and not 0. Long story why, and no point explaining since it is off-topic to this question.
If needed, this is the code that is creating the array. It is being pulled from an uploaded CSV file.
$csv_array = array(array());
if (!empty($_FILES['upload_csv']['tmp_name']))
{
$file = fopen($_FILES['upload_csv']['tmp_name'], 'r');
}
if($file)
{
while (($line = fgetcsv($file)) !== FALSE)
{
$csv_array[] = array_combine(range(1, count($line)), array_values($line));
}
fclose($file);
}
So in conclusion, I need to modify my if statement
to check whether the array is empty or not.
Thanks in advance!
So simply check for if the first key is present in array or not.
Example
if(!empty($csv_array[1]))
{
//My code goes here if the array is not empty
}