linuxbashwindow-management

Linux : Get window border height


I try to get in a bash script the maximal size of a window (i.e. the size of the screen minus the panels on the edges of the screen). I am using Kubuntu but if it could work for any linux system it would be great.

Currently, my solution is to maximize the active window via wmctrl :

wmctrl -r :ACTIVE: -b add,maximized_horz,maximized_vert

and then get the size of the window thanks to xwininfo :

xwininfo -id $(xdotool getactivewindow)

Unfortunately, I don't get the size of the window but the size of the window and it's border (if I remove the border, I get the expected value).

So my questions are :

1 - Is there a command to remove the border of a window ? (I only know how to do it manually)

2 - Is there a better way to do this ? (if it can be done without maximizing a window it could be great)

Thanks in advance for your help


Solution

  • I realised that what I was calling border was in fact the title bar... If I use xwininfo -stats I indeed get the border width (0 in my case). The title bar height (after maximizing the window) is obtained in the field Absolute upper-left. The following gives me the expected height :

    eval $(xwininfo -id $(xdotool getactivewindow) | sed -n -e "s/^  Height: \+\([0-9]\+\).*/Height=\1/p" -e "s/^  Absolute upper-left Y:  \+\([0-9]\+\).*/HeightTitleBar=\1/p")
    Height=$(($Height+$HeightTitleBar))
    

    Thanks for your help !