Find indexes from list in Elixir

With Enum.find_index/2, we can find the index of an element. However, if a same element occurs several times, how can we do?

I would like to have this behavior:

iex> find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "a" end)
[0]

iex> find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "c" end)
[2]

iex> find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "b" end)
[1, 3, 4]

Thanks for any ideas.

I couldn't find a exact function in library, so tried to implement it. Hope it can help some.

defmodule Sample1 do
  # combining Enum functions
  def find_indexes(collection, function) do
    Enum.filter_map(Enum.with_index(collection), fn({x, _y}) -> function.(x) end, elem(&1, 1))
  end
end

defmodule Sample2 do
  # implementing as similar way as Enum.find_index
  def find_indexes(collection, function) do
    do_find_indexes(collection, function, 0, [])
  end

  def do_find_indexes([], _function, _counter, acc) do
    Enum.reverse(acc)
  end

  def do_find_indexes([h|t], function, counter, acc) do
    if function.(h) do
      do_find_indexes(t, function, counter + 1, [counter|acc])
    else
      do_find_indexes(t, function, counter + 1, acc)
    end
  end
end

IO.puts "Sample1"
IO.inspect Sample1.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "a" end)
IO.inspect Sample1.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "c" end)
IO.inspect Sample1.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "b" end)

IO.puts "Sample2"
IO.inspect Sample2.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "a" end)
IO.inspect Sample2.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "c" end)
IO.inspect Sample2.find_indexes(["a", "b", "c", "b", "b"], fn(x) -> x == "b" end)

Executed as follows,

% elixir find.ex
Sample1
[0]
[2]
[1, 3, 4]
Sample2
[0]
[2]
[1, 3, 4]