Is there a way to declare 32-bit floating point value in C++ - ensuring that it will always be 32 bits regardless of platform/compiler?
I can do that for integers like that:
#include <stdint.h>
uint32_t var; //32 bit unsigned integer
uint64_t var1; //64 bit unsigned integer
is there a way to do something like that for floats? As far as I know,
float var; //Usually is 32 bit, but NOT GUARANTEED to be 32 bit
is implementation specific, and is not necessarily 32 bit.. (Correct me if I am wrong).
I am using qt, so if there is any solution using it I would accept it - I couldn't find anything like quint16 for floats (qreal changes size depending on platform).
You're using Qt. which is specific to C++, so I'm not sure why the question is tagged C.
As far as I know, on all platforms where Qt is supported, type float
is 32-bit IEEE.
If somebody decides to port Qt to, say, a Cray vector machine with 64-bit float
, you're not going to have a 32-bit floating-point type anyway (unless you implement it yourself in software, but I don't see how that would be useful).
There is no <stdfloat.h>
/ <cstdfloat>
corresponding to <stdint.h>
/ <cstdint>
. C and C++ provide float
, double
, and long double
, and imposes minimal requirements on them, but doesn't give you a way to ask for a floating-point type of any specific size.
Your best bet is probably to add something like this in main
, or in some function that's guaranteed to be called during program startup:
assert(CHAR_BIT * sizeof (float) == 32);
and perhaps CHAR_BIT == 8
as well if your code implicitly depends on that.
It's unlikely that the assert
will ever fire -- and if it does, you've got bigger problems.
You might want to reconsider whether you really need a 32-bit floating type. If your code were running on a system with 64-bit float
, how would that fail to meet your requirements?