pythonargparse

How to open file using argparse?

I want to open file for reading using argparse. In cmd it must look like: my_program.py /filepath

That's my try:

parser = argparse.ArgumentParser()
parser.add_argument('file', type = file)
args = parser.parse_args()

This gives me [edit: added later from comment by OP]:

parser.add_argument('file', type = file) NameError: name 'file' is not defined
Solution

  • The type of the argument should be string (which is default anyway). So make it like this:

    parser = argparse.ArgumentParser()
parser.add_argument('filename')
args = parser.parse_args()
with open(args.filename) as file:
  # do stuff here