Editor's note: Judging by later comments by the OP, the gist of this question is: How can you convert a file with CRLF (Windows-style) line endings to a LF-only (Unix-style) file in PowerShell?
Here is my powershell script:
$original_file ='C:\Users\abc\Desktop\File\abc.txt'
(Get-Content $original_file) | Foreach-Object {
$_ -replace "'", "2"`
-replace '2', '3'`
-replace '1', '7'`
-replace '9', ''`
-replace "`r`n",'`n'
} | Set-Content "C:\Users\abc\Desktop\File\abc.txt" -Force
With this code i am able to replace 2 with 3, 1 with 7 and 9 with an empty string. I am unable to replace the carriage return line feed with just the line feed. But this doesnt work.
You have not specified the version, I'm assuming you are using Powershell v3.
Try this:
$path = "C:\Users\abc\Desktop\File\abc.txt"
(Get-Content $path -Raw).Replace("`r`n","`n") | Set-Content $path -Force
Editor's note: As mike z points out in the comments, Set-Content appends a trailing CRLF, which is undesired. Verify with: 'hi' > t.txt; (Get-Content -Raw t.txt).Replace("`r`n","`n") | Set-Content t.txt; (Get-Content -Raw t.txt).EndsWith("`r`n"), which yields $True.
Note this loads the whole file in memory, so you might want a different solution if you want to process huge files.
UPDATE
This might work for v2 (sorry nowhere to test):
$in = "C:\Users\abc\Desktop\File\abc.txt"
$out = "C:\Users\abc\Desktop\File\abc-out.txt"
(Get-Content $in) -join "`n" > $out
Editor's note: Note that this solution (now) writes to a different file and is therefore not equivalent to the (still flawed) v3 solution. (A different file is targeted to avoid the pitfall Ansgar Wiechers points out in the comments: using > truncates the target file before execution begins). More importantly, though: this solution too appends a trailing CRLF, which may be undesired. Verify with 'hi' > t.txt; (Get-Content t.txt) -join "`n" > t.NEW.txt; [io.file]::ReadAllText((Convert-Path t.NEW.txt)).endswith("`r`n"), which yields $True.
Same reservation about being loaded to memory though.