Python try except

try:
    #statement 1
    #statement 2
except Exception, err:
    print err
    pass

This may be very trivial but I never actually thought about it until now and I found myself not being able to answer the following questions:

1. Does statement 2 gets executed if an error is raised in statement 1?

2. How does Exception deal with in a case where an error is raised for both statement 1 and statement 2? Which error does it print out in the above code? Both?

The answer is "no" to both of your questions.

As soon as an error is thrown in a try/except block, the try part is immediately exited:

>>> try:
...     1/0
...     print 'hi'
... except ZeroDivisionError, e:
...     print 'error'
...
error
>>>

As you can see, the code never gets to the print 'hi' part, even though I made an except for it.

You can read more here.