Counting how many values were attributed to a key an a python (3.2) dictionary

I am sure this is silly, but I simply cannot get around it. I have a dictionary, like this, with unequal number of values for each key:

'John greased ': ['axle', 'wheel', 'wheels', 'wheel', 'engine', ''], 
'Paul alleged ': ['truth', 'crime', 'facts', 'infidelity', 'incident', ''], 
'Tracy freed ': ['animals', 'fish', 'slaves', 'slaves', 'slaves', 'pizza'], 
'Lisa plowed ': ['field', 'field', '', '', '', ''],

I want to know how many values there are for each key, not each unique value but how many tokens there are per key, repeated or not. So I would have a result like:

John greased  5
Paul alleged  5
Tracy freed  6
Lisa plowed  2

I was trying to use this to work it out using the code bellow:

for key, value in sorted(result.items()):
         print(key, len(value)) 

But because of the missing values all the lengths turn out to be the same. Any ideas on how to solve this or where to find it out? Thanks a lot for any help.

One way to solve this, is by changing your last line:

print(key, len([item for item in value if item])) 

So your complete code:

ITEMS = {
    'John greased ': ['axle', 'wheel', 'wheels', 'wheel', 'engine', ''],
    'Paul alleged ': ['truth', 'crime', 'facts', 'infidelity', 'incident', ''],
    'Tracy freed ': ['animals', 'fish', 'slaves', 'slaves', 'slaves', 'pizza'],
    'Lisa plowed ': ['field', 'field', '', '', '', ''],
}

for key, value in ITEMS.items():
    #print value
    print(key, len([item for item in value if item]))

You can also use filter with bool:

print(key, len(filter(bool, value)))

So, the loop:

for key, value in ITEMS.items():
    #print value
    print(key, len(filter(bool, value)))

You need to apply list over filter like so print(key, len(list(filter(bool, value)))) in Python 3.