Studying for my OCA Java SE 7 Programmer I exam, so newbie question. I have an example question I do not understand. The following code compiles, but gives a ClassCastException at runtime:
interface Roamable {
}
class Phone {
}
public class Tablet extends Phone implements Roamable {
public static void main(String... args) {
Roamable var = (Roamable) new Phone();
}
}
When I change Roamable var = (Roamable) new Phone();
into Roamable var = (Roamable) new String();
I get a compilation error right away.
Two questions:
new Phone()
, but doesn't it compile with new String()
?Why does the code above compile at all? Phone seems unrelated to Roamable to me?
yes because Roamable
is an interface it might cause a Run-time exception but not compile time exception, because even if Phone
doesn't implement Roamable
, a subclass of Phone
might, hence the compiler has no way to know it but at the Run time.
It is already defined in java language specification. Check out my answer here.
Why does the code compile with new Phone(), but doesn't it compile with new String()?
Because class String
is declared as public final class
in java.lang
package. As specified in jls 8.1.1.2 final class
section: a class declared as final
can't be extended and hence it won't have any subclass. So, the compiler already knows that String
can't be extended: hence no subclass's existence is possible to implement interface Roamable
Edit: (With response to your below comment)
Let us assume that B
is a subclass of A
which implements an interface T
.
Now an statement :
T t = (T)new A();
is essentially same as:
A aObj = new A() ;
T t = (T)aObj ; // a run-time exception happen
before running into conclusion, let us do the same thing with an object of B
:
A aObj = new B();
T t = (T)aObj; // no exception happen.
so, the real reason with super class and sub class here is the reference. The aObj
class in this second code example is also an instance of class A
but it is also an instance of class B
which has implemented T
.