I would like to do a search, and I would like to start traversing from 2 labels (OR condition). For example, I need to find out all the nodes which have labels either 'Male' or 'Female' and whose property, name =~ '.ail.'.
You can put this condition in the WHERE clause:
MATCH (n)
WHERE n:Male OR n:Female
RETURN n
EDIT
As @tbaum points out this performs an AllNodesScan. I wrote the answer when labels were fairly new and expected the query planner to eventually implement it with a NodeByLabelScan for each label, as it does for the single label case
MATCH (n)
WHERE n:Male
RETURN n
I still think this is a reasonable expression of the query and that it is reasonable to expect the query planner to implement it with label scans, but as of Neo4j 2.2.3 the query is still implemented with an AllNodesScan and a label filter. Here is therefore a more verbose alternative. Since the label disjunction signifies a set union and this union can be expressed in different ways, we can express it in a way that the query planner implements without scanning all nodes, and instead starts with a NodeByLabelScan per label.
MATCH (n:Male)
WHERE n.name =~ '.ail.'
RETURN n
UNION MATCH (n:Female)
WHERE n.name =~ '.ail.'
RETURN n
This means expressing the query once for each label and joining them with an explicit UNION. This is not unreasonable, at least for smaller number of labels, but it's not clear to me why the query planners shouldn't be able to infer the same implementation from the simpler query so I have opened a github issue here.