Consider this
void f(vector<const T*>& p)
{
}
int main()
{
vector<T*> nonConstVec;
f(nonConstVec);
}
The following does not compile.The thing is that vector<T*>
can not be converted to vector <const T*>
, and that seems illogically to me , because there exists implicit conversion from T*
to const T*
. Why is this ?
vector<const T*>
can not be converted to vector <T*>
too, but that is expected because const T*
can not be converted implicitly to T*
.
I've added a few lines to your code. That's sufficient to make it clear why this is disallowed:
void f(vector<const T*>& p)
{
static const T ct;
p.push_back(&ct); // adds a const T* to nonConstVec !
}
int main()
{
vector<T*> nonConstVec;
f(nonConstVec);
nonConstVec.back()->nonConstFunction();
}