I want to parse the following string to a date in go:
"This item will be released on March 9, 2014."
I followed this and came up whith:
func findReleaseDateString(raw string) time.Time {
test, err := time.Parse("This item will be released on January 2, 2006.", raw)
if err != nil {
panic(err)
}
return test
}
Which works like a charm for english strings.
My problem: I would like to parse german strings. Like:
"Dieser Artikel wird am 9. März 2014 erscheinen."
I am aware, that I could match day, month and year via a regex and then parse it. But is there any possibility to tell time.Parse to use a different set of constants for month?
There is currently no i18n support for the time package. While waiting for that to happen, you can try using a wrapper package such as:
As stated by monday
's documentation:
Monday is not an alternative to standard time package. It is a temporary solution to use while the internationalization features are not ready.
That's why monday doesn't create any additional parsing algorithms, layout identifiers. It is just a wrapper for time.Format and time.ParseInLocation and uses all the same layout IDs, constants, etc.
Here is your example using monday
:
package main
import (
"fmt"
"github.com/goodsign/monday"
"time"
)
func findReleaseDateString(raw string) time.Time {
loc, _ := time.LoadLocation("Europe/Berlin")
t, err := monday.ParseInLocation("Dieser Artikel wird am 2. January 2006 erscheinen.", raw, loc, monday.LocaleDeDE)
if err != nil {
panic(err)
}
return t
}
func main() {
t := findReleaseDateString("Dieser Artikel wird am 9. März 2014 erscheinen.")
fmt.Println(t)
}
Output:
2014-03-09 00:00:00 +0100 CET