[SOLVED] Pass system date and time as a filename in C++

Pass system date and time as a filename in C++

I wanted to make an Attendance system which would take system date and time as file name of the file for ex: this is how normally it is

int main () {
time_t t = time(0);   // get time now
struct tm * now = localtime( & t );
cout << (now->tm_year + 1900) << '-'
     << (now->tm_mon + 1) << '-'
     <<  now->tm_mday
     << endl;
  ofstream myfile;
  myfile.open ("example.txt");
  myfile << "Writing this to a file.\n";
  myfile.close();
  return 0;
}

but i want system date and time in place of example.txt i have calculated time by including ctime header file in the program above program is just example .

Solution

You can use strftime() function to format time to string,It provides much more formatting options as per your need.

int main (int argc, char *argv[])
{
     time_t t = time(0);   // get time now
     struct tm * now = localtime( & t );

     char buffer [80];
     strftime (buffer,80,"%Y-%m-%d.",now);

     std::ofstream myfile;
     myfile.open (buffer);
     if(myfile.is_open())
     {
         std::cout<<"Success"<<std::endl;
     }
     myfile.close();
     return 0;
}