I am new to Python and I have become stuck with printing the elements of an array separated by a delimiter. My array consists of 60 000 odd rows with 26 elements per row, some of the elements only contain numbers, while others contain an assortment of characters including special characters. Example:
a[0] = [abc,123,a1b2c3,*wewqe,...]
a[1] = [098i,qwerty,123qwe,xx-u,...]
I would like the output to be(without a "|" after the last element and each row on their own line:
abc|123|a1b2c3|*wewqe,...
098i|qwerty|123qwe|xx-u,...
I have tried the following, but they do not work:
for row in results :
length = len(row)
print("")#throw in a new line
print ("Number of elements: " + str(length))
print '|'.join((str(row)))
And this:
for row in results :
length = len(row)
print("")#throw in a new line
print ("Number of elements: " + str(length))
for item in row:
print '|'.join(str(item))
And this:
for row in results :
length = len(row)
print("")#throw in a new line
print ("Number of elements: " + str(length))
for item in row:
print item,
All of the above produces results, but not the results I would like. Thank you in advance.
print '|'.join(map(str, row))
join takes a sequence of strings. row is a sequence of... something, so map(str, row) turns it into a sequence of strings. If the elements of row are already strings (and they should be), you can just do
print '|'.join(row)
On Python 3, you can still use '.'.join, or you can use the sep argument to Python 3's print function:
print(*row, sep='|')
which will tell print to put a | between printed items instead of the usual space.