Does the C++ compiler optimize the multiply by two operation x*2
to a bitshift operation x<<1
?
I would love to believe that yes.
Actually VS2008 optimizes this to x+x:
01391000 push ecx
int x = 0;
scanf("%d", &x);
01391001 lea eax,[esp]
01391004 push eax
01391005 push offset string "%d" (13920F4h)
0139100A mov dword ptr [esp+8],0
01391012 call dword ptr [__imp__scanf (13920A4h)]
int y = x * 2;
01391018 mov ecx,dword ptr [esp+8]
0139101C lea edx,[ecx+ecx]
In an x64 build it is even more explicit and uses:
int y = x * 2;
000000013FB9101E mov edx,dword ptr [x]
printf("%d", y);
000000013FB91022 lea rcx,[string "%d" (13FB921B0h)]
000000013FB91029 add edx,edx
This is will the optimization settings on 'Maximize speed' (/O2)