How to enumerate a recursive datatype in Haskell?

This blog post has an interesting explanation of how to use the Omega monad to enumerate an arbitrary grammar diagonally. He offers an example of how to do so, resulting in an infinite sequence of strings. I'd like to do the same, except that, instead of generating a list of strings, it generates a list of an actual datatype. For example,

 data T = A | B T | C T T

Would generate

A, B A, C A A, C (B A) A... 

Or something similar. Unfortunately my Haskell skills are still maturing and after some hours playing it I couldn't manage to do what I want. How can that be done?

As requested, one of my attempts (I have tried too many things...):

import Control.Monad.Omega

data T = A | B T | C T T deriving (Show)

a = [A] 
        ++ (do { x <- each a; return (B x) })
        ++ (do { x <- each a; y <- each a; return (C x y) })

main = print $ take 10 $ a

My first ugly approach was:

allTerms :: Omega T
allTerms = do
  which <- each [ 1,2,3 ]
  if which == 1 then
    return A
  else if which == 2 then do
    x <- allTerms
    return $ B x
  else do
    x <- allTerms
    y <- allTerms
    return $ C x y

But then, after some cleaning up I reached this one liner

import Control.Applicative
import Control.Monad.Omega
import Control.Monad

allTerms :: Omega T
allTerms = join $ each [return A, B <$> allTerms, C <$> allTerms <*> allTerms]

Note that order matters: return A has to be the first choice in the list above, or allTerms will not terminate. Basically, the Omega monad ensures a "fair scheduling" among choices, saving you from e.g. infiniteList ++ something, but does not prevent infinite recursion.

An even more elegant solution was suggested by Crazy FIZRUK, exploiting the Alternative instance of Omega.

import Control.Applicative
import Data.Foldable (asum)
import Control.Monad.Omega

allTerms :: Omega T
allTerms = asum [ pure A
                , B <$> allTerms
                , C <$> allTerms <*> allTerms
                ]