I have a main
branch with a file called app.js
. I made changes to this file on an experiment
branch.
I want to apply only the changes made to app.js
from experiment
onto the main
branch.
git checkout main # first get back to main
git checkout experiment -- app.js # then copy the version of app.js
# from branch "experiment"
See also Undo working copy modifications of one file in Git.
With the new git switch
and git restore
commands, that would be:
git switch main
git restore --source experiment -- app.js
By default, only the working tree is restored.
If you want to update the index as well (meaning restore the file content, and add it to the index in one command):
git restore --source experiment --staged --worktree -- app.js
# shorter:
git restore -s experiment -SW -- app.js
As Jakub Narębski mentions in the comments:
git show experiment:path/to/app.js > path/to/app.js
works too, except that, as detailed in the SO question "How to retrieve a single file from specific revision in Git?", you need to use the full path from the root directory of the repo.
Hence the path/to/app.js used by Jakub in his example.
As Frosty mentions in the comment:
you will only get the most recent state of app.js
But, for git checkout
or git show
, you can actually reference any revision you want, as illustrated in the SO question "git checkout revision of a file in git gui":
$ git show $REVISION:$FILENAME
$ git checkout $REVISION -- $FILENAME
would be the same is $FILENAME is a full path of a versioned file.
$REVISION
can be as shown in git rev-parse
:
experiment@{yesterday}:app.js # app.js as it was yesterday
experiment^:app.js # app.js on the first commit parent
experiment@{2}:app.js # app.js two commits ago
and so on.
schmijos adds in the comments:
you also can do this from a stash:
git checkout stash -- app.js
This is very useful if you're working on two branches and don't want to commit.