JavaScript for-loop: Skip 2 Numbers Followed by a set of 3

I made a JavaScript loop that skips every set of two numbers that are followed by a set of three.

Consider the following set of integers:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10

This is what the array returns:

1, 2, 3, 6, 7, 8

See how it skipped 4-5 and 9-10? (every set of two numbers followed by a set of three)

Visual:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 (skips bolded numbers)

Here is what I came up with:

var y = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

    for (var i = 0; i < y.length; i++) {
        if (y[i] >= 4 && y[i] <= 5) {
            continue;
        }
        if (y[i] >= 9 && y[i] <= 10) {
            continue;
        }
        document.write(y[i]);
    }

The above for-loop returns 123678 from 12345678910. The problem is that I had to manually say which ones to skip. Is there a way, possibly with % modulus, to automatically skip every set of two numbers followed by a set of three without limiting the length to ten?

You could just keep a counter instead

for (var i=0, j=0; i < y.length; i++) {

    if (j < 3) {
        document.write(y[i]);
    } else if ( j > 3) {
        j = -1;
    }

    j++;
}

FIDDLE